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- Stan Wawrinka (ATP 20) defeats Andrej Rublew (ATP 8) in the round of 16 at Paris-Bercy with 1: 6, 6: 4, 6: 3.
- The Swiss finished an 11-game winning streak for the 23-year-old Russian.
- In the quarterfinals on Friday, Wawrinka will meet world number 7 Alexander Zverev.
Stan Wawrinka and Andrei Rublew had to wait a long time before they could reach their final sixteen. It wasn’t until 10.30pm that the two entered the courthouse in the Bercy neighborhood of Paris. By the time the Swiss won, it was already past midnight.
Rublew has had 11 straight wins lately. And at the start of the match, everything indicated that the number 12 would follow against Wawrinka. The Lausanne player was simply overwhelmed by the powerful play – especially the forehand – of his 23-year-old opponent.
Rublew loses focus
But Wawrinka managed to flip the switch. Although he was able to significantly reduce his error rate and served better than the opening sentence, his counterpart broke. At the latest when the Swiss broke 4: 3 with a great return winner, the thread broke at Rublew.
In the third set, Wawrinka seamlessly built on her great performance and, in addition to her running skills, she also repeatedly demonstrated her good hand. Rublew, who recently won tournaments in St. Petersburg and Vienna, has clearly been served. A backhand on the net marked his defeat after 1:41 hours. A defeat that at first he had not even mentioned.
Another difficult task awaits Wawrinka in Friday’s quarter-finals. The Swiss meets Alexander Zverev (ATP 7). The German showed some problems in the round of 16 against Jordan Thompson, but ultimately won in 3 sets.
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